Question

# Block 1, of mass m 1 =9.50 kg , moves along a frictionless air track with...

Block 1, of mass m 1 =9.50 kg , moves along a frictionless air track with speed v 1 =27.0 m/s . It collides with block 2 m2 =13.0 kg , which was initially at restThe blocks stick together after the collision.

Find the Magnitude p1 of the total inital momentum of the two block system.

Find vf, the magnitude of the final velocity of the two block system.

Part A.

Initial moment of system will be given by:

Pi = m1*u1 + m2*u2

m1 = mass of block 1 = 9.50 kg

m2 = mass of block 2 = 13.0 kg

u1 = Initial speed of block 1 = 27.0 m/s

u2 = Initial speed of block 2 = 0 m/s

So,

Pi = 9.50*27.0 + 13.0*0

Pi = 256.5 kg.m/sec

Part B.

Since there was no external force applied, So momentum of system before and after collision will remain coonserved, So

Pi = Pf

Pf = (m1 + m2)*V

V = final speed of two block system = ?

So

Pi = Pf = (m1 + m2)*V

V = 256.5/(9.50 + 13.0)

V = 11.4 m/s

Let me know if you've any query.

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