Question

Block 1, of mass m 1 =9.50 kg , moves along a frictionless air
track with speed v 1 =27.0 m/s . It collides with block 2 m2 =13.0
kg , which was initially at restThe blocks stick together after the
collision.

Find the Magnitude p1 of the total inital momentum of the two
block system.

Find vf, the magnitude of the final velocity of the two block
system.

Answer #1

Part A.

Initial moment of system will be given by:

Pi = m1*u1 + m2*u2

m1 = mass of block 1 = 9.50 kg

m2 = mass of block 2 = 13.0 kg

u1 = Initial speed of block 1 = 27.0 m/s

u2 = Initial speed of block 2 = 0 m/s

So,

Pi = 9.50*27.0 + 13.0*0

**Pi = 256.5 kg.m/sec**

Part B.

Since there was no external force applied, So momentum of system before and after collision will remain coonserved, So

Pi = Pf

Pf = (m1 + m2)*V

V = final speed of two block system = ?

So

Pi = Pf = (m1 + m2)*V

V = 256.5/(9.50 + 13.0)

**V = 11.4 m/s**

**Let me know if you've any query.**

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