Question

Mary is an avid game show fan and one of the contestants on a popular game show. She spins the wheel and after 1.5 revolutions, the wheel comes to rest on a space that has a $1,500.00 prize. If the initial angular speed of the wheel is 3.15 rad/s, find the angle through which the wheel has turned when the angular speed is 1.90 rad/s. (Answer in Rev)

Answer #1

Then , given data wi = 3.15 rad/a

wf= 1.90 rad/s

Mary is an avid game show fan and one of the contestants on a
popular game show. She spins the wheel and after 1.5 revolutions,
the wheel comes to rest on a space that has a $1,500.00 prize. If
the initial angular speed of the wheel is 3.50 rad/s, find the
angle through which the wheel has turned when the angular speed is
2.10 rad/s.
rev

Starting from rest, a fan accelerates with constant angular
acceleration. At one time it is rotating at 10 rev/s; 20
revolutions later, its angular speed is 150 rev/s.
(a) The angular acceleration.
(b) The time required by the fan to complete the 20
revelations.
(c) The number of revolutions from rest until the fan reaches
the 10 rev/s angular speed.

on a game show a contestants have a chance to spin a wheel. the
wheel is divided into slots, half of the slots say win and half say
lose. there is a pointer above the top of the wheel, if the pointer
points to a win slot when the wheel stops then the contestant wins
cash prize. if the pointer points to a lose slot then the
contestant wins nothing. The contestant spins the wheel 3 times.
Let x be...

A wheel released from rest is rotating with constant angular
acceleration of 2.5 rad/s2.
(a) After 2.5 s, what is its angular velocity?
rad/s
(b) Through what angle has the wheel turned?
rad
(c) How many revolutions has it made?
rev
(d) What is the speed of a point 1.0 m from the axis of
rotation?
m/s
What is the magnitude of the total acceleration of the same
point?
m/s2

QUESTION 3
An electric fan is turned off, and it slows down from 356
revolutions/s to 80.1 revolutions/s in 4.07 seconds. How many times
did the fan blades spin in this time?
QUESTION 4
A disk rotates about a fixed axis through its center of mass and
perpendicular to the disk. It starts from rest and accelerates
uniformly, reaching angular speed ω after 8.44
revolutions. If it continues to accelerated at the same rate, how
many more revolutions would it...

Please show work, I'm having trouble answering these :(
1)A bicycle with 0.3 m radius wheels, is moving such that the
angular speed of each wheel is 75 rad/s. If the bicyclist then
applies the brakes and the wheels slow with an angular acceleration
of -15 rad/s2, how many revolutions will each wheel make before the
bike stops?
A. 188 revolutions
B. 1.07e4 revolutions
1C.14.7 revolutions
D. 62.7 revolutions
E.29.8 revolutions
2)You tie the loose end of a 0.1 kg...

On the Wheel of Fortune game show, a solid wheel (of radius 7.4
m and mass 10 kg) is given an initial counterclockwise angular
velocity of +1.11 rad/s. It then smoothly slows down and stops
after rotating through 3/4 of a turn.
(a) Find the frictional torque that acts to stop the
wheel.
= N · m
(b) Assuming that the torque is unchanged, but the mass of the
wheel is halved and its radius is doubled. How will this affect...

Assessment
Identify the Variables!
In rotational kinematics - the variables are:
t = time, which is measured in s (for seconds)
θ = angle = what angle did the object turn thru, usually
measured radians
ωO = initial angular velocity = the rotational speed
of the object at the beginning of the problem, which is measured in
rad/s
ω = final angular velocity = the rotational speed of the object
at the end of the problem, which is measured in...

A wheel at rest is accelerated with uniform angular acceleration
4.6 rad/s2. How many revolutions does it take for the wheel to
achieve 857 rev/min?
A child is sitting a distance 8 m from the center of a
merry-go-round that is 18.6 m in diameter. If the merry-go-round
makes 8.8 rev/min, what is the velocity of the child in m/s?
An object is in circulation motion at a speed of 499 rad/sec
when it begins to slow down at a...

A child pushes her friend (m = 25 kg) located at a radius r =
1.5 m on a merry-go-round (rmgr = 2.0 m, Imgr
= 1000 kg*m2) with a constant force F = 90 N applied
tangentially to the edge of the merry-go-round (i.e., the force is
perpendicular to the radius). The merry-go-round resists spinning
with a frictional force of f = 10 N acting at a radius of
1 m and a frictional torque τ = 15 N*m...

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