Question

Billiard ball A of mass mA = 0.118 kg moving with speed vA = 2.80 m/s strikes ball B, initially at rest, of mass mB = 0.135 kg . As a result of the collision, ball A is deflected off at an angle of θ′A = 30.0∘ with a speed v′A = 2.10 m/s, and ball B moves with a speed v′B at an angle of θ′B to original direction of motion of ball A.

Taking the x axis to be the original direction of motion of ball A, choose the correct equation expressing the conservation of momentum for the components in the y direction.

0=(mAvA+mBv′B)sinθ′B0=mAv′Asinθ′A−mBv′Bsinθ′BmAvA=mAv′Acosθ′A+mBv′Bcosθ′BmAvA=mAv′Acosθ′A−mBv′Bsinθ′B

Solve these equations for the angle, θ′B, of ball B after the collision. Do not assume the collision is elastic.

Solve these equations for the speed, v′B, of ball B after the collision. Do not assume the collision is elastic.

Answer 1