Question

Billiard ball A of mass mA = 0.125 kg moving with speed vA = 2.80 m/s strikes ball B, initially at rest, of mass mB = 0.138 kg . As a result of the collision, ball A is deflected off at an angle of θ′A = 30.0∘ with a speed v′A = 2.10 m/s, and ball B moves with a speed v′B at an angle of θ′B to original direction of motion of ball A.

(a) Solve these equations for the angle, θ′B, of ball B after the collision. Do not assume the collision is elastic.

(b)Solve these equations for the speed, v′B, of ball B after the collision. Do not assume the collision is elastic.

Answer #1

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Billiard ball A of mass mA = 0.130 kg moving with speed vA =
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As a result of the collision, ball A is deflected off at an angle
of 30.5 ∘ with a speed vA1 = 2.35 m/s .
C.) Solve for the speed, vB1, of ball B. Do not assume the
collision is elastic.
D.) Solve for the angle, θB, of ball B. Do...

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