Question

A small container of water is placed on a carousel inside a microwave oven, at a...

A small container of water is placed on a carousel inside a microwave oven, at a radius of 12.0 cm from the center. The turntable rotates steadily, turning through one revolution in each 7.25 s. What angle does the water surface make with the horizontal?

Most people that have answered this question have answered it along the lines of this:

"The water is traveling in a circle whose radius, r, is .12m (I like to convert all units to kg/m/sec for simplicity). The speed of the water is the distance it travels divided by the time it takes. The circumference of the circle is 2*Pi*r = 0.7536m. It travels this is 7.25sec, so the speed is

0.7536m/7.25sec = .1039m/s

Now we find the centripetal acceleration required for the circular motion: a = v^2/r

plugging our velocity and radius:

a = (.1039m/s)^2/(.12m) = 0.09m/sec^2

Acceleration is a vector, so there is direction. In circular motion it is toward the center of the microwave. Due to the inertia of the water (it wants to go in a straight line, see Newton's Laws) the water will appear to be pulled outward, the "centrifugal force". Now we'll compare our acceleration (pointing horizontally outward) to gravity (pointing straight down).

We add these two vector accelerations to find the net acceleration. Since they are orthogonal (perpendicular) you get A = 0.09(x)+9.81(y). To find the angle of the water from horizontal, you find the direction of A.

This is Atan(x/y) = Atan(0/09/9.81)= 0.52 degrees "

I have come to terms that this is the correct answer to this problem however I cannot find any one that can explain why mg is being considered the x component for this problem, please help!

Homework Answers

Answer #1

'mg' is the y component. Centrifugal force is acting in the x direction.

The shape of water surface depends on the forces acting on it.

For this problem, we have to find net acceleration of the water mass.(Consider water as a mass that can change it's shape)

To find the net acceleration, we must find net force.(Resultant of all the forces acting on the body)

As stated in the solution, one force is the centrifugal force.

Water has mass. It is constantly being pulled down by the gravity with an acceleration of 9.8m/s2 . Assuming the mass of the water as m, Gravity force acting on the water is mg .

So, Net force on water = centrifugal(outwards) + mg(straight down)

x component y component

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
1. For a stationary ball of mass m = 0.200 kg hanging from a massless string,...
1. For a stationary ball of mass m = 0.200 kg hanging from a massless string, draw arrows (click on the “Shapes” tab) showing the forces acting on the ball (lengths can be arbitrary, but get the relative lengths of each force roughly correct). For this case of zero acceleration, use Newton’s 2nd law to find the magnitude of the tension force in the string, in units of Newtons. Since we will be considering motion in the horizontal xy plane,...
It is common to see birds of prey rising upward on thermals. The paths they take...
It is common to see birds of prey rising upward on thermals. The paths they take may be spiral-like. You can model the spiral motion as uniform circular motion combined with a constant upward velocity. Assume a bird completes a circle of radius 6.00 mevery 5.00 s and rises vertically at a rate of 3.00 m/s. 1. Find the speed of the bird relative to the ground. Express your answer using three significant figures. 2. Find the magnitude of the...
One end of a cord is fixed and a small 0.550-kg object is attached to the...
One end of a cord is fixed and a small 0.550-kg object is attached to the other end, where it swings in a section of a vertical circle of radius 2.50 m, as shown in the figure below. When θ = 18.0°, the speed of the object is 6.50 m/s. An object is swinging to the right and upward from the end of a cord attached to a horizontal surface. The cord makes an angle θ with the vertical. An...
One end of a cord is fixed and a small 0.250-kg object is attached to the...
One end of a cord is fixed and a small 0.250-kg object is attached to the other end, where it swings in a section of a vertical circle of radius 1.00 m, as shown in the figure below. When θ = 22.0°, the speed of the object is 8.50 m/s. An object is swinging to the right and upward from the end of a cord attached to a horizontal surface. The cord makes an angle θ with the vertical. An...
An unsuspecting bird is coasting along in an easterly direction at 3.00 mph when a strong...
An unsuspecting bird is coasting along in an easterly direction at 3.00 mph when a strong wind from the south imparts a constant acceleration of 0.200 m/s2. If the wind\'s acceleration lasts for 3.00 s, find the magnitude r and direction θ (measured counterclockwise from the easterly direction) of the bird\'s displacement over this time interval. (HINT: assume the bird is originally travelling in the x direction and there are 1609 m in 1 mile.) r=? theta=? Now, assume the...
Your task will be to derive the equations describing the velocity and acceleration in a polar...
Your task will be to derive the equations describing the velocity and acceleration in a polar coordinate system and a rotating polar vector basis for an object in general 2D motion starting from a general position vector. Then use these expressions to simplify to the case of non-uniform circular motion, and finally uniform circular motion. Here's the time-dependent position vector in a Cartesian coordinate system with a Cartesian vector basis: ⃗r(t)=x (t) ̂ i+y(t) ̂ j where x(t) and y(t)...
Question 1 The study of Uniform Circular Motion relates to objects traveling with constant speed around...
Question 1 The study of Uniform Circular Motion relates to objects traveling with constant speed around a circle with radius, R. Since the object has a constant speed along a circular path, we can also say that A) the object has zero velocity. B) the object has a constant acceleration magnitude. C) the object has zero acceleration. D) the object has a constant velocity. E) the object has an increasing acceleration. Question 2 Uniform Circular Motion (UCM) problems are just...
A rock is tied to a string and spun in a circle of radius 1.4 m...
A rock is tied to a string and spun in a circle of radius 1.4 m as shown in the figure below. The speed of the rock is 13 m/s. (c) What is the total force on the rock directed toward the center of its circular path? Express your answer in terms of the (unknown) tension T in the string. (Use the following as necessary: ?.) F = (d) Apply Newton's second law along both the vertical and the horizontal...
An eagle is circling looking for prey, it completes a circle of radius 10 m every...
An eagle is circling looking for prey, it completes a circle of radius 10 m every 5 s. Birds can use their skills to make air exert a force on them in any direction. a) Draw a diagrams of the eagle’s motion, indicate the velocity vector and the coordinate system. b) What are the linear and angular speed of the eagle? c) If the eagle increases its speed over thirty seconds, to complete one circle (r=10m) every 3s, calculate the...
1) You are making a circular turn in your car on a horizontal road when you hit a big patch of ice, causing the force of friction between the tires and the road to become zero. While the car is on the ice, it
1) You are making a circular turn in your car on a horizontal road when you hit a big patch of ice, causing the force of friction between the tires and the road to become zero. While the car is on the ice, itA) moves along a straight-line path away from the center of the circle.B) moves along a straight-line path toward the center of the circle.C) moves along a straight-line path in its original direction.D) continues to follow a...