Question

Four 2.7 V cells are connected in series to a 12 lightbulb. If the resulting current is 0.41 A, what is the internal resistance of each cell, assuming they are identical and neglecting the wires?

Answer #1

The total resistance of the circuit is given by the Ohm's law

Since, net voltage will be the sum of all voltages in the series. So,

12 Ohm resistance is due to the light bulb.

So, net internal resistance will be

Thus, internal resistance of each cell is

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