Chapter 18, Problem 1 |
A 47- resistor and a 29- resistor are connected in series across a 24-V battery. What is the voltage across (a) the 47- resistor and (b) the 29- resistor?
Chapter 18, Problem 2 |
The current in a 63- resistor is 0.077 A. This resistor is in series with a 42- resistor, and the series combination is connected across a battery. What is the battery voltage?
Chapter 18, Problem 3 |
What resistance must be placed in parallel with a 172- resistor to make the equivalent resistance 111 ?
Chapter 18, Problem 4 |
Two resistors, 59 and 82 , are connected in parallel. The current through the 82- resistor is 2.8 A. (a) Determine the current in the other resistor. (b) What is the total power consumed by the two resistors?
Chapter 18, Problem 5 |
Find the equivalent resistance between points A and B in the drawing.
Chapter 18, Problem 6 |
Find the equivalent resistance between points A and B in the drawing.
Chapter 18, Problem 7 |
A 68- resistor is connected in parallel with a 151- resistor. This parallel group is connected in series with a 25- resistor. The total combination is connected across a 23-V battery. Find (a) the current and (b) the power dissipated in the 151- resistor.
Chapter 18, Problem 8 |
A new "D" battery has an emf of 1.5 V. When a wire of negligible resistance is connected between the terminals of the battery, a current of 24 A is produced. Find the internal resistance of the battery.
Chapter 18, Problem 9 |
Two batteries, each with an internal resistance of 0.015 , are connected as in the drawing. In effect, the 9.0-V battery is being used to charge the 8.0-V battery. What is the current in the circuit?
Chapter 18, Problem 10 |
Determine the magnitude of the current in the (a) 8.0- and (b) 2.0- resistors in the drawing.
Chapter 18, Problem 11 |
An electronic flash attachment for a camera produces a flash by using the energy stored in a 890-F capacitor. Between flashes, the capacitor recharges through a resistor whose resistance is chosen so the capacitor recharges with a time constant of 3.9 s. Determine the value of the resistance.
Chapter 18, Problem 12 |
The circuit in the drawing contains two resistors and two capacitors that are connected to a battery via a switch. When the switch is closed, the capacitors begin to charge up. What is the time constant for the charging process?
1)
(a)
i = V/(R1+R2) = 24/(47+29) = 0.316 A
across 47 = V1 = i*R1 = 0.316*47 = 14.852 v
(b) across 29 = V2 = i*R2 = 0.316*29 = 9.164 V
(2)
V = i*(R1+R2) = 0.077*(63+42) = 8.805 V
(3)
1/Req = 1/R1 + 1/R2
1/111 = 1/172 + 1/R2
R2 = 312.9
(4)
(a)
in series current is same
through 59 = 2.8 A
(b)
P = i^2(R1+R2) = 2.8^2*(59+82) = 1105.44 W
(7)
Req = (151*68)/(151+68) + 25 = 72 ohms
I = V/Req = 23/72 = 0.32 A
current through 151 = (I*68)/(151+68) = 0.099
A
power = 0.099^2*151 = 1.48 W <<---answer
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