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Derive the equation for the stoichiometric air-to-fuel ratio for the combustion a given hydrocarbon (CxHy).Your final...

Derive the equation for the stoichiometric air-to-fuel ratio for the combustion a given hydrocarbon (CxHy).Your final answer should be in terms of the ratio y/x.

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Answer #1

General combustion reaction of hydrocarbon

Now determine the stoichiometric coefficients in products

For C:

= x

H:

2=y

N2:

=3.76*

O2

total moles of air

nair =

Air fuel mass ratio = mass of air / mass of fuel

AFmass= mair / mfuel

Air fuel mole ratio = mole of air / mole of fuel

AFmole= nair / nfuel

Mair = 29 g/mol

nair =

n fuel = 1 mol

M fuel = 12x + y

(AF) mass = 4.76(x + y/4)*29 / 1*(12x + y)

= 138(x + y/4) / (12x + y)

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