Question

Given that, at 650?C phosphine decomposes as: 4PH3 --> P4(g) + 6H2, -rphos = (10 hr-1 ) Cphos you were asked to estimate the size of a plug flow reactor operating at 649?C and 11.4 atm to achieve 75% conversion of 10 mol/hr of phosphine in a 2/3 phosphine; 1/3 inert feed. It turns out that the reaction order is actually zero, all the other information remaining the same. What will your re-estimate of the reactor volume be?

Answer 1