3) The corrosion of iron is an electrochemical process that involves the standard reduction potentials given here at 25 °C. Fe2+(aq) + 2e– → Fe(s) E° = –0.44 V O2(g) + 4H+ (aq) + 4e– → 2H2O(l) E° = +1.23 V
a. Calculate the voltage for the standard cell based on the corrosion reaction. 2Fe(s) + O2(g) + 4H+ (aq) → 2Fe2+(aq) + 2H2O(l)
b. Calculate the voltage if the reaction in Part a occurs at pH = 4.00 but all other concentrations are maintained as they were in the standard cell.
c. For the reaction Fe(OH)2(s) + 2e– → Fe(s) + 2OH– (aq), E° = –0.88 V. Use this information with one of the given standard potentials in Appendix ** to calculate the Ksp of Fe(OH)2.
Solution :
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