STAR Co. provides paper to smaller companies whose volumes are not large enough to warrant dealing directly with the paper mill. STAR receives 100-feet-wide paper rolls from the mill and cuts the rolls into smaller rolls of widths 12, 15, and 30 feet. The demands for these widths vary from week to week. The following cutting patterns have been established:
Number of: | ||||
Pattern | 12ft. | 15ft. | 30ft. | Trim Loss |
1 | 0 | 4 | 1 | 10 ft. |
2 | 4 | 3 | 0 | 7 ft. |
3 | 8 | 0 | 0 | 4 ft. |
4 | 2 | 1 | 2 | 1 ft. |
5 | 2 | 3 | 1 | 1 ft. |
Trim loss is the leftover paper from a pattern (e.g., for pattern 4, 2(12) + 1(15) + 2(30) = 99 feet used resulting in 100-99 = 1 foot of trim loss). Orders in hand for the coming week are 5,670 12-foot rolls, 1,680 15-foot rolls, and 3,350 30-foot rolls. Any of the three types of rolls produced in excess of the orders in hand will be sold on the open market at the selling price. No inventory is held.
Optimal Solution:
(a) |
Formulate an integer programming model that will determine how many 100-foot rolls to cut into each of the five patterns in order to minimize trim loss. If your answer is zero enter “0” and if the constant is "1" it must be entered in the box.
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(a) Integer programming model is following:
Let x1, x2, x3, x4, x5 be the number of 100-ft rolls to be cut into pattern 1,2,3,4,5 resp
Minimize 10x1+7x2+4x3+1x4+1x5
s.t.
0x1+4x2+8x3+2x4+2x5 >= 5670
4x1+3x2+0x3+1x4+3x5 >= 1680
1x1+0x2+0x3+2x4+1x5 >= 3350
x1, x2, x3, x4, x5 integers
(b) Solution of the model using LINDO is following:
Optimal solution:
x4 = 2835
All other variables = 0
Trim loss = 2835 feet
(c) 2835 rolls of 100 ft should be cut in pattern 4.
Excess rolls produced of 12-ft size and sold in open market = 2835*2 - 5670 = 0
Excess rolls produced of 15-ft size and sold in open market = 2835*1 - 1680 = 1155
Excess rolls produced of 30-ft size and sold in open market = 2835*2 - 3350 = 2320
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