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given the equation of a line ax+by+c=0 how can i find the normal vector to it??

given the equation of a line ax+by+c=0 how can i find the normal vector to it??

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Answer #1

We have found out the slope of the tangent to the line ax+by+c=0 Which is given by dy/dx and it comes out to be

-a/b. Thus, the vector from (0,0) to (a,b) would work as the Normal vector to the given line, as explained in the solution provided below, step by step.

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