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Find the antiderivative of r'(t)=cos(2t)i−2sintj+11+t2kr'(t)=cos(2t)i−2sintj+11+t2k that satisfies the initial condition r(0)=3i−2j+k.

Find the antiderivative of r'(t)=cos(2t)i−2sintj+11+t2kr'(t)=cos(2t)i−2sintj+11+t2k that satisfies the initial condition r(0)=3i−2j+k.

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