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Given that the acceleration vector is a(t)=(-9 cos(3t))i+(-9 sin(3t))j+(-5t)k, the initial velocity is v(0)=i+k, and the...

Given that the acceleration vector is a(t)=(-9 cos(3t))i+(-9 sin(3t))j+(-5t)k, the initial velocity is v(0)=i+k, and the initial position vector is r(0)=i+j+k, compute:

A. The velocity vector v(t)

B. The position vector r(t)

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