Question

Solve the following initial value problem, showing all work. Verify the solution you obtain.

*y**''**-2**y**'**+y=0;
y**0**=1,*
*y**'**0**=-2.*

Answer #1

:)

For 2y' = -tan(t)(y^2-1) find general solution (solve for y(t))
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Solve the following initial value problem.
y''-2y'+2y=4x+5. ; y(0)=3. and y'(0)=0

For the initial value problem
• Solve the initial value problem.
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Solve the initial value problem: y''−2y'+y=e^t/(1+t^2), y(0) =
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Then ﬁnd α so that the solution approaches zero as t →∞

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1
differential eq

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?x′ = 2y−x
y′ = 5x−y
Initial Conditions:
x(0)=2
y(0)=1

solve the following initial value problem x' = 2xy
y' = y -2t +1 x(0) = x0 y(0) =
y0

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and determine where the solution attains its maximum value (for
0≤x≤0.339). Enclose arguments of functions in parentheses. For
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y(x)=
The solution attains a maximum at the following value of x.
Enter the exact answer.
x=

Solve the initial value problem. 5d^2y/dt^2 + 5dy/dt -
y = 0; y(0)=0, y'(0)=1

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