Question

What are Singular solutions in differential equations..

How to find them.Can we find them using the general solution.

Could you give me a explanation

Answer #1

ALL THE BEST ...!!

Series Solutions Near a regular singular point:
Find two linearly independent solutions to the given differential
equation.
3x2y"-2xy'-(2+x2)y=0

Find the general solutions for the following differential
equations:
a. (D^2 - 8D + 16)y = 0
b. (D^4 - 9D^3)y = 0

Series Solutions of Ordinary Differential Equations For the
following problems solve the given differential equation by means
of a power series about the given point x0. Find the recurrence
relation; also find the first four terms in each of two linearly
independed sollutions (unless the series terminates sooner). If
possible, find the general term in each solution.
y"+k2x2y=0, x0=0,
k-constant

Find the general solutions of the given systems of differential
equations in the following problem.
x'=3x-2y+et
y'=x

Find the general solutions of the given systems of differential
equations in the following problem.
x'=x+3y+16t
y'=x-y-8

-What is a singular solution using
for?
-By providing an example of real mechanical or electrical
system, discuss linearity different
-Give some applications of first-order
separable equations

differential equations!
find the Differential Equation General Solve by using
variation of parameters method...
y''' - 3y'' +3y' - y =12e^x

Differential Equations
Using the method of undetermined coefficients find the Yp
(particular solution) of the differential equation: y’’ - y = 1 +
e^x

Solve the following second order differential equations:
(a) Find the general solution of y'' − 2y' = sin(3x) using the
method of undetermined coefficients.
(b) Find the general solution of y'' − 2y'− 3y = te^−t using the
method of variation of parameters.

This is a differential equations problem:
use variation of parameters to find the general solution to the
differential equation given that y_1 and y_2 are linearly
independent solutions to the corresponding homogeneous equation for
t>0. ty"-(t+1)y'+y=18t^3 ,y_1=e^t ,y_2=(t+1)
it said the answer to this was C_1e^t + C_2(t+1) -
18t^2(3/2+1/2t)
I don't understand how to get this answer at all

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 33 minutes ago

asked 42 minutes ago

asked 45 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago