Question

differential equations!

find the Differential Equation General Solve by using variation of parameters method...

y''' - 3y'' +3y' - y =12e^x

Answer #1

Find the general solution to the following differential equation
using the method of variation of parameters.
y"-2y'+2y=ex csc(x)

Solve the following second order differential equations:
(a) Find the general solution of y'' − 2y' = sin(3x) using the
method of undetermined coefficients.
(b) Find the general solution of y'' − 2y'− 3y = te^−t using the
method of variation of parameters.

Use the method of variation parameters to find the
general solution of the differential equation
y'' +16y = csc 4x

3. Find the general solution if the given differential equation
by using the variation of parameters method. y''' + y'= 2 tan x, −
π /2 < x < π/2

Solve the differential equation by variation of parameters.
y'' + 3y' + 2y = 1 / (7 + e^x)

Solve Differential equation by variation of parameters method.
y"-5y'+6y=e^x

Solve the following differential equations by using variation of
parameters.
y''-y'-2y=e3x

Solve the differential equation by variation of parameters. y''
+ 3y' + 2y = 1/(4+e^x)

a) Find the general solution of the differential equation
y''-2y'+y=0
b) Use the method of variation of parameters to find the general
solution of the differential equation y''-2y'+y=2e^t/t^3

By using method of variation of parameters the particular
solution of the following differential equation
y″+y=sec2(x)
is

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