No there will only be one PBE in this case. The case can be better potrayed by the gift game example on the Wikipedia page. Here the payoff for the player depends on the payoff of the player 2 only. If 2 accepts the payoff of 2 is 1, which makes the payoff of A type 1 and B type 0. Similarly if payoff of 2 is 0, the payoff of A is also 0 and that of B is 1. This is a hypothetical payoff matrix mentioned above but the gist of the argument is the same. The PBE will be the same as the gift example of the wiki page.
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