Question

Computer Networks

An image is 1200 × 800 pixels with 3 bytes/pixel. Assume the image is uncompressed. Calculate the required time to transmit it over: a- a 56-kbps modem channel b- a 1-Mbps cable modem c- a 10-Mbps Ethernet d- a 100-Mbps Ethernet e- a gigabit Ethernet

Answer 1

Given :

Image is 1200 X 800 pixels with 3 bytes/pixel

First, we need to calculate the total size of image.

Size = Total pixels * bytes per second

size = 1200 * 800 * 3

= 2880000 bytes

Now, we need to convert the size of image in bits. To convert in bits, simply multiply with 8

Size of image in bits = 2880000 * 8

= 23040000 bits

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a) Transmission of Image on 56-kbps modem channel:

Here, 56 kbps means 56 kilibits per second. Convert this in bits per second.

therefore it transact 56000 bits/second

Required time to transmit = Size of image / speed of modem

Required time to transmit = 23040000 / 56000

= 411.428 seconds

Hence, required time to transmit the image over a 56 kbps modem channel is 411.428 seconds.

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b) Transmission of Image on 1 Mbps cable modem :

Here, 1 Mbps means 1 Megabits per second. Convert this in bits per second.

therefore it transact 1000000 bits/second

Required time = 23040000 / 1000000

= 23.04 seconds.

Hence, required time to transmit the image over a 1 Mbps cable modem is 23.04 seconds.

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c) Transmission of Image on 10 Mbps Ethernet :

Here, 10 Mbps means 10 Megabits per second. Convert this in bits per second.

therefore it transact 10000000 bits/second

Required time = 23040000 / 10000000

= 2.304 seconds.

Hence, required time to transmit the image over a 1 Mbps cable modem is 2.304 seconds.

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d) Transmission of image on 100 Mbps ethernet:

Here, 100 Mbps means 100 Megabits per second. Convert this in bits per second.

therefore it transact 100000000 bits/second

Required time = 23040000 / 100000000

= 0.2304 seconds.

Hence, required time to transmit the image over a 1 Mbps cable modem is 0.2304 seconds.

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e) Transmission of image on gigabit ethernet:

Here, gigabit means 1000,000,000 bits per second. Convert this in bits per second.

therefore it transact 1000,000,000 bits/second

Required time = 23040000 / 1000,000,000

= 0.02304 seconds.

Hence, required time to transmit the image over a 1 Mbps cable modem is 0.02304 seconds.

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