Question

C++ problem:

Write a function that:

• accepts three integers as it's only arguments
• computes the average of the arguments
• returns the average without loss of precision
• does not use global variables
• does not interact with the user in any way

Answer 1

double average(int n1, int n2, int n3) {
    return (n1 + n2 + n3) / 3.0;
}

#include <iostream>

using namespace std;

double average(int n1, int n2, int n3);

int main() {
    int n1, n2, n3;
    cout << "Enter three integers: ";
    cin >> n1 >> n2 >> n3;
    cout << "Average is " << average(n1, n2, n3) << endl;
    return 0;
}

double average(int n1, int n2, int n3) {
    return (n1 + n2 + n3) / 3.0;
}