Question

C++ What does this filter do? char ch; while (can.get(ch)) { if (ispunct(ch)) continue; count.put(ch); }...

C++

What does this filter do?

char ch;

while (can.get(ch))

{

if (ispunct(ch)) continue;

count.put(ch);

}

a. prints only punctuation characters in input

b. endless loop if input contains punctuation: otherwise prints all input

c. prints all non-punctuation characters in input

d. prints all characters before first punctuation character

e. endless loop when first punctuation character encountered

Homework Answers

Answer #1

Answer: C (prints all non-punctuation characters in input)

Explanation:  So below code first take user input using cin.get in ch variable. ispunct function checks for input character and returns 1 if it is a punctuation character and 0 if it is not so. When you enter any punctuation character, it will simply continue the loop to get next character otherwise it put the character on console using cout.put.

#include <iostream>
using namespace std;

int main()
{
    char ch;
    //it will be a loop to get character
    while (cin.get(ch))
    {
        //if it is a punctuation character then continu to get next character
        if (ispunct(ch)) continue;
        //if not a punctuation then print it
        cout.put(ch);
    }
}
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