Question

def zigzag(text): Implement a function that takes a string and returns a new string that is...

def zigzag(text): Implement a function that takes a string and returns a new string that is a zig-zag rearrangement of it like the one in the examples below.

• Parameters: text is a string (no validation needed)

• Examples:

zigzag('12345678') → '18273645'

zigzag('123456789') → '192837465'

zigzag('abcdefgh') → 'ahbgcfde'

zigzag('GeorgeMason') → 'GneoosragMe'

In Python please!

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Answer #1 
def zigzag(s):
    i = 0
    j = len(s)-1
    res = ""
    while(i<j):
        res += (s[i]+s[j])
        i+=1
        j-=1
    if(len(s)%2==1):
        res += s[i]
    return res

# Testing
print(zigzag('12345678'))
print(zigzag('123456789'))
print(zigzag('abcdefgh'))
print(zigzag('GeorgeMason'))

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