Question

Write a Python function to count the number of even numbers from a list of numbers.

Write a Python function that takes a list and returns a new list with unique elements of the first list.
Sample List : [1,2,3,3,3,3,4,5]
Unique List : [1, 2, 3, 4, 5]

Answer 1

(Be careful with indentation of lines in python. If you still have any doubts regarding this question please comment I will definitely help)

1).

Explanation:

• Call the even_count() function by passing the list x
• initialize count to 0
• run for loop from 0 to len(x)
• Use the condition x[i]%2==0. If yes then increment count.
• After coming out of for loop return count.
• print the count

Code to find number of even numbers in a list:

def even_count(x):
count = 0
for i in range(len(x)):
if(x[i]%2==0):
count=count+1
return count

x = [2,3,9,6,5,10,8,12,14]
n = even_count(x)
print("number of even numbers in the list is: ",n)

O/P:

number of even numbers in the list is: 6

Code and O/P screenshot:

Here in the input list there are 6 even numbers. So it prints 6

2).

Code Explanation:

• pass the list x to the unique_list() function
• In the function initially declare an empty list named unique
• Then run a for loop from 0 to length of list
• Inside the for loop use the condition if(x[i] not in unique). then unique.append(x[i])
• This condition adds elements to the list unique if the element is not present in the unique list which doesnot add the same element again
• return the unique list

Code to return unique elements of the list:

def unique_list(x):
unique = []
for i in range(len(x)):
if(x[i] not in unique):
unique.append(x[i])
return unique

x = [1,2,3,3,3,3,4,5]
print(unique_list(x))

O/P:

[1, 2, 3, 4, 5]

Code and O/P screenshot: