Question

question: Complete the function remove number such that given a list of integers and an integer n, the function removes every instance of
n from the list. Remember that this function needs to modify the list, not return a new list.
please edit the Python form without errors

def remove_number(lst: List[int], number: int) -> None:
    """
        Remove every instance of number in lst. Do this
        *in-place*, i.e. *modify* the list. Do NOT
        return a new list.

    >>> lst = [1, 2, 3]
    >>> remove_number(lst, 3)
    >>> lst
    [1, 2]
    """

    pass

Answer 1

To remove all the instances of a number from the list, traverse the list using for loop.

Compare each element with the number that has to be removed from the list. If the element matches the number, remove that element from the list.

The function remove_number is defined as follows:

def remove_number(lst,number): 
    #remove all occurrences of the number 
    for i in lst: 
        if(i == number): 
            lst.remove(i) 

Creation of the list and call the function remove_number()

Complete code snippet with output: