Question

C Programming

Load txt file into char array with eight elements. Each new line will be a different array with eight new elements

num.txt is written
0x16 0x38 0x59 0x79 0x17 0x39 0x56 0x78

0x17 0x38 0x58 0x78 0x19 0x30 0x57 0x78

should result into

char num[8] = {0x16, 0x38, 0x59, 0x79, 0x17, 0x39, 0x56, 0x78};

char num2[8] = {0x17, 0x38, 0x58, 0x78, 0x19, 0x30, 0x57, 0x78 };

Answer 1

#include <stdio.h>

int main(void) {

FILE *fp;

fp=fopen("num.txt","r");

char num1[8],num2[8];

int i=0,j=0,x;

unsigned int data;

while(fscanf(fp,"%x",&data)!=-1) //read data from file till end of file is reached

{

if(i<8) //store first eight elements

num1[i++]=data;

else

num2[j++]=data; //stores next eight elements

}

for(x=0;x<i;++x)

printf("%#x ",num1[x]);

printf("\n");

for(x=0;x<j;++x)

printf("%#x ",num2[x]);

return 0;

}

num.txt

0x16 0x38 0x59 0x79 0x17 0x39 0x56 0x78
0x17 0x38 0x58 0x78 0x19 0x30 0x57 0x78

Output