Question

The following code is not portable for a particular reason. What is that reason and what...

The following code is not portable for a particular reason. What is that reason and what problem does it have? This code is in C.

char c = 148;

int i = 2000;

printf(“i divided by c is %d\n”, i / c);

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Answer #1

Portability Of C program:

Firstly, C programs are meant to be portable as long as your desired target platform has a working C compiler available, you can move your C source code that target platform by recompiling it, without having to modify it.

Problem :

The above code is not portable because of few exceptions of char datatype whether signed or unsigned (the standards aren't specified, that is to make C code portable we cannot make assumptions on the size of any data type other than char).

It's mostly portable. It has standard libraries - but not all OSes support all features in the same way. You CAN write code that's specific to particular operating systems.

The output of the program:

  i divided by c is -18

Reason: There is no specification of char datatype whether it is signed or unsigned because of this the code may not be portable,

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