Question

Convert the following C program to inline assembly int main(){ int i; printf("Hex Dec Oct Ch\n");...

Convert the following C program to inline assembly

int main(){
int i;

printf("Hex Dec Oct Ch\n");

for (i = 32; i < 256; i++){
printf("%2x %3d %3o %c\n",i,i,i,i);
}

return 0;
}

the code below shows where to do the assembly at:

int main(){
int i = 0;
char *hdr = "Hex Dec Oct Ch\n";
char *msg = " %2x %3d %3o %c\n";

printf("%s\n",hdr);

———asm{
// DO ASSEMBLY HERE
}
system("pause");

}

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Homework Answers

Answer #1 
.LC0:
  .string "Hex Dec Oct Ch"
.LC1:
  .string "%2x %3d %3o %c\n"
main:
  push rbp
  mov rbp, rsp
  sub rsp, 16
  mov edi, OFFSET FLAT:.LC0
  call puts
  mov DWORD PTR [rbp-4], 32
  jmp .L2
.L3:
  mov esi, DWORD PTR [rbp-4]
  mov ecx, DWORD PTR [rbp-4]
  mov edx, DWORD PTR [rbp-4]
  mov eax, DWORD PTR [rbp-4]
  mov r8d, esi
  mov esi, eax
  mov edi, OFFSET FLAT:.LC1
  mov eax, 0
  call printf
  add DWORD PTR [rbp-4], 1
.L2:
  cmp DWORD PTR [rbp-4], 255
  jle .L3
  mov eax, 0
  leave
  ret
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