Question

1) A client uses TCP to send 100 bytes data, with minimum 20 bytes header at TCP and IP layers each, and minimum 40 bytes header/trailer at Ethernet layer. Explain the

i) efficiency of encapsulation process at each of TCP, IP and Ethernet layers showing the fractions (numerator and denominator without solving), in first box below.

ii) Next, calculate the efficiency in % (ratio of useful data to total bytes, i.e. goodput data) at TCP, IP and Ethernet layers. Use one decimal place in your answer.

Answer 1

The message overhead includes:

· TCP: 20 bytes of header

· IP: 20 bytes of header

· Ethernet: total 40 bytes of header and trailer.

1. The efficiency is given as:

L = 100 bytes, 100/120 ----TCP

L = 100 bytes, 100/120 ----IP

L = 100 bytes, 100/140 ---Ethernet

The fractions are given above.

2. The efficiency persentage is given as follows:

100/120 *100=83.33% ----------TCP

100/120 *100=83.33% ----------IP

100/140 *100=71.42% --------Ethernet

Efficiency is given above,

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