Question

Please use Python 3+

Write a function called let_to_num. It should take a word and encode it into a series
of numbers and dashes, with the numbers corresponding to the position of
the letter in the alphabet (regardless of casing). If the character is 
not a letter, then ignore it.

Examples of outputs:

print(let_to_num('AZ'))   # -> 1-26
print(let_to_num(''))     # -> (empty string)
print(let_to_num('A?Z'))  # -> 1-26
print(let_to_num('AZ?'))  # -> 1-26
print(let_to_num('AbzC')) # -> 1-2-26-3

Answer 1

Python code:

#defining let_to_num function
def let_to_num(word):
    #initializing num as an empty string
    num=""
    #initializing flag as False
    flag=False
    #looping each character in the word
    for i in word:
        #checking if it is a alphabet
        if(i.isalpha()):
            #adding it encoded number to num
            num+=str(ord(i.upper())-64)+"-"
            #setting flag as True
            flag=True
    #checking if flag is True
    if(flag):
        #returning the encoded number
        return num[:-1]
    #returning empty string
    return num
#calling let_to_num function and printing result
print(let_to_num('AZ'))
#calling let_to_num function and printing result
print(let_to_num(''))
#calling let_to_num function and printing result
print(let_to_num('A?Z'))
#calling let_to_num function and printing result
print(let_to_num('AZ?'))
#calling let_to_num function and printing result
print(let_to_num('AbzC'))

Screenshot:

Output: