Question

Phone number lookup
Design a program that has two parallel arrays: a string array named people that is initialized with the names of seven of your friends, and a string array named phoneNumbers that is initialized with your friends phone numbers. The program should allow the user to enter a persons name (or part of a persons name). it should then search for that person in the people array. If the person is found, it should get that persons phjone number from the phoneNumbers array and display it. If the person is not found in the people array, the program should display a message indicating so.

Can you create a Raptor flowchart, not a pseudocode I already have a pseudocode

Here is a pseudocode

//Constant to hold array sizes.

Constant Integer SIZE = 7

//Array to hold name of friends.

Declare String people[SIZE] = "Ashton Jones", "Mia Ray",

"Penelope Waters", "Mark Grey",

"Stephen Jordan","Rebecca Smith",

"Robert Cheney"

//Array to hold each friend phone numbers.

Declare String phoneNumbers[SIZE] = 8958845, 1898123,

8441294, 7480652, 556278, 5450562, 1210755

//Variable to hold name to be searched.

Declare String name

//Variable to use as a loop variable.

Declare Integer index = 0

// Boolean Variable to indicate whether the name of the //friend is found in the array or not. It is initialized //to false.

Declare Boolean found = False

//Variable to store the index value where name is found.

Declare Integer foundIndex

//Get name from user.

Display "Enter name."

Input name

//Sequential search to find the name in the array.

While Found == False AND index <= SIZE - 1

If contains(people[index],name) Then

Set found = True

Set foundIndex = index

Else

Set index = index + 1

End If

End While

//Display if the name is found or not. If the name is in

//the people array then display their phone number.

If Found == True Then

Display "The phone number of ", people[foundIndex]

Display " is ", phoneNumbers[foundIndex]

Else

Display "The name ", name " is NOT in the people array"

End If

Answer 1

#include <iostream>
using namespace std;

int main()
{
//declaring persons names
string names[]={"Uday","John","Smith","Rocky","Bolt","Mike","Paul"};
string n;
//declaring phone numbers
int phones[]={991212,994312,994532,889943,990121,932143,909012};
//reading person name
cout<<"Enter name of the person: ";
cin>>n;
int index=-1;
//starting iterating the person array
for(int i=0;i<7;i++){
//checking if it is equal to given name
//if yes exit loop
if(names[i]==n){
index=i;
break;
}

}
//printing the output
if(index==-1){
cout<<n<<" does not exist in the list ";
}
else{
cout<<n<<"'s phone number is : "<<phones[index];
}

return 0;

}