Question

#include int main() { const size_t num_lists = 3; float* a[num_lists]; size_t sizes[num_lists] = {6, 6, 6}; for(int k=0; k < 3; k++) { a[k] = (float*)malloc(sizes[k] * sizeof(float)); } // ... } Now consider the array a. Match each expression to the data type of the expression's value:

(float, float*,float**,float*[3])

a   

a[2]

a[2][1]

&a[2][1]

&a[2]

*a

Answer 1

Given code to us:
#include
int main()
{
const size_t num_lists = 3;
float *a[num_lists];
size_t sizes[num_lists] = { 6, 6, 6 };
for (int k = 0; k < 3; k++)
{
a[k] = (float*) malloc(sizes[k] *sizeof(float));
}
..
}

Answer:

a is array of float pointers: data type of a is float**
a[2] is a float pointer, it points to an array of floats: data type of a[2] is float*
a[2][1] is a float, it is an element in array pointed by a[2]: data type of a[2][1] is float
&a[2][1] is the address of float element: data type of a[2][1] is float*
&a[2] it the address of float pointer: data type of &a[2] is float**
*a dereferences to a[0], since a[0] is a float pointer: data type of *a is float*

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