Question

#include<iostream>
using namespase std;
int main()
{
    int i=1;
    int j=-5;
    int k=80;
    float f=2.22;
    float h=-7.5;
    char a='S';
    char b='M';
    cout<<i<<"\t"<<j<<"\t"<<k<<endl;
    Cout<<f<<"\t"<<h<<endl;
    cout<<a<<"\t"<<b<<endl;
    return 0;
    }

Answer 1

#include<iostream>
using namespace std;
int main()
{
    int i=1;
    int j=-5;
    int k=80;
    float f=2.22;
    float h=-7.5;
    char a='S';
    char b='M';
    cout<<i<<"\t"<<j<<"\t"<<k<<endl;
    cout<<f<<"\t"<<h<<endl;
    cout<<a<<"\t"<<b<<endl;
    return 0;
}

The code in question is wrong use namespace instead of namespase and your second Cout is wrong which should be cout. you can follow the code.