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If you burn methane with 50% excess air, what would be the flue gas composition?

If you burn methane with 50% excess air, what would be the flue gas composition?

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Answer #1

Stoichiometric Equation for combustion of alkanes in air

here

Here the case is of methane

a=1

b=4/2=2

z=1+2/2=2

c=3.76*2=7.52

If there is no excess air

then combustion equation becomes

If there is excess 50% air

then air amount should multiplied with 1.5 (since total air 150%)

ie

air becomes

then the equation will be

There fore fuel gas composition will be as shown above

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