Question

An equal-tangent crest vertical curve is 1919.200m long and connects a +2.5%and –1.5%grade. If the design speed of the roadway is 88.5 kph, does this curve have adequate passing-sight distance?

Answer #1

An equal-tangent crest vertical curve is being designed for a
speed of 55 mph. The curve connects grades of 2% and -3.5% in the
direction of interest. The curve high point is at station 110+00
and has an elevation of 500 ft. What is the station and elevation
of the PVC and the PVI?

A vertical summit curve has tangent grades of +2.5% and -1.5%
intersecting at station 12+460.12 at an elevation of 150m above sea
level. If the length of the curve is 182m:
a. Compute the length of the passing sight distance.
b. Compute the stationing of the highest point of the curve.
c. Compute the elevation of the highest point of the curve.

) An equal-tangent crest vertical curve is designed for 100
km/h. The initial grade is +3.4% and the final grade is negative.
Draw the curve. What is the elevation difference between the PVC
and the high point of the curve?

A vertical crest curve on a single carriageway road with a
design speed of 100km/h is to be built in order to join as
ascending grade of 3% with a descending grade of 3%. The motorist’s
eye height is assumed to be 1.05m while the object height is
assumed to be 0.26m. 1. Calculate the minimum curve length required
in order to satisfy the requirement of minimum sight stopping
distance. 2. Recalculate the minimum curve length with the object
height...

An
existing equal-tangent sag vertical curve is designed for 60 mi/h.
The initial grade is -3% and the elevation of the PVT is 754 ft.
The PVC of the curve is at station 134 + 16 and the PVI is at 137 +
32. An overpass is being constructed directly above the PVI. The
highway is for cars only (AASHTO minimum and recommended structure
clearances do not apply) and the overpass design assumes the
driver's eye height is set conservatively...

An existing equal-tangent sag vertical curve is designed for 60
mi/h. The initial grade is -3% and the elevation of the PVT is 754
ft. The PVC of the curve is at station 134 + 16 and the PVI is at
137 + 32. An overpass is being constructed directly above the PVI.
The highway is for cars only (AASHTO minimum and recommended
structure clearances do not apply) and the overpass design assumes
the driver's eye height is set conservatively...

A sag vertical curve is to join a grade of g1=−3.25% to a grade
of g2=−1.00%. What is the minimum length of the curve for
acceptable passing sight distance at night, with headlight
illumination?

A 1,800 ft. long sag vertical curve (equal tangent) has PVC at
Station 145+10 and elevation 1,280 ft. The initial grade is -2.5%
and final grade is +4.8%. Determine the elevation and stationing of
PVI and PVT.

A crest vertical curve joining a +3 percent and a -4 percent
grade is to be designed with a length of 2184 ft and the Station of
BVC is ( 334 + 68) at an elevation of 217.24 ft. The distance from
BVC at station (339 + :00) is

i would really appreciated if answer this question quickly thank
you all !
An equal-tangent crest vertical curve is designed for 100 km/h.
The initial grade is +3.4% and the final grade is negative. Draw
the curve. What is the elevation difference between the PVC and the
high point of the curve?

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