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The value of Kc for the reaction between water vapor and dichlorine monoxide is 0.0900 at...

The value of Kc for the reaction between water vapor and dichlorine monoxide is 0.0900 at 25C.

H2O + ClO2 ---> 2HOCl

Determine the equilibrium concentrations of all three compounds if the starting concentrations of both reactants are 0.00352 M, with [HOCl]0 = 0.000 M.

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Answer #1

Kc = 0.09

Kc = [HOCl]^2 / [H2O][ClO2]

initially

[H2O] = 0.00352

[ClO2] = 0.00352

[HOCl] = 0

in euqilibrium

[H2O] = 0.00352 -x

[ClO2] = 0.00352 - x

[HOCl] = 0 + 2x

then

0.09 = [HOCl]^2 / [H2O][ClO2]

0.09  =(2x)^2 / (0.00352 - x)^2

sqrt(0.09) = 2x / (0.00352 - x)

0.3 = 2x/ (0.00352 - x)

0.3* (0.00352 - x) = 2x

0.3* (0.00352) - 0.3x = 2x

0.001056 - 0.3x = 2x

2.3x = 0.001056

x = 0.001056 /2.3

x = 0.0004591

[H2O] = 0.00352 -0.0004591 = 0.0030609

[ClO2] = 0.00352 - 0.0004591 = 0.0030609

[HOCl] = 0 + 2*0.0004591 = 0.0009182 M

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