Question

Pure dry nitrogen monoxide gas can be made reacting potassium nitrite, potassium nitrate, and chromium (lll) oxide. The products are nitrogen monoxide and potassium chromate. How many grams of nitrogen monoxide can be produced from a reaction mixture containing 5 moles of each reactant?

Answer 1

Chromium(III) oxide react with potassium nitrite and potassium nitrate to produce potassium chromate and nitric oxide. This reaction takes place at a temperature of 400-500°C.

Cr₂O₃ + 3KNO₂ + KNO₃ 2K₂CrO₄ + 4NO

According to the above equation KNO2 will be consumed 3 equivalent while other 2 reactants will consume one equivalent. Hence KNO2 will become limiting reagent

5 Moles KNO2 will produce (5 x 4 /3) 6.66 Moles of NO

6.66 Moles of NO = 6.6 x 30.006 = 200.04 gm

Hence 200.04 gm of NO can be produced