Calculate the ratio of "acetic / acetate" concentrations that must exist in a buffer solution of pH = 5.00. Deduce the pH change that will occur if one liter of the previous solution, which is 0.10 M in acetic, is added 50 ml of 1.00 M HCl.
Ka of acetic acid = 1.80 x 10-5
pKa of acetic acid = -log(Ka) = -log(1.80 x 10-5) = 4.74
According to Henderson-Hasselbach equation,
pH = pKa + log([conjugate base] / [acid])
where [conjugate base] = concentration of conjugate base = concentration of acetate
[acid] = concentration of acid = concentration of acetic acid
pKa = 4.74
pH = 5.00
substituting the values,
5.00 = 4.74 + log([acetate] / [acetic acid])
log([acetate] / [acetic acid]) = 5.00 - 4.74 = 0.26
[acetate] / [acetic acid] = 100.26
[acetate] / [acetic acid] = 1.80
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