Question

Given the number of moles of benzoic acid necessary to react with 40mL of a 0.1...

Given the number of moles of benzoic acid necessary to react with 40mL of a 0.1 NaOH solution. How many grams of benzoic acid must be added to 100ml of water to react with a 1:1 stochiometry with the NaOH?

Science   Chemistry   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Calculate the pH of a solution that contains 1.675 moles of benzoic acid and 0.925 moles...
Calculate the pH of a solution that contains 1.675 moles of benzoic acid and 0.925 moles of sodium benzoate (conjugate base of benzoic acid) in 8.00L. How many milliliters of 1.00 M NaOH must be added to raise the pH of the solution by 0.25?​
A buffer solution is prepared by adding 0.5 moles of benzoic acid (C6H5COOH, Ka = 6.3...
A buffer solution is prepared by adding 0.5 moles of benzoic acid (C6H5COOH, Ka = 6.3 x 10-5) and 0.5 moles of potassium benzoate (C6H5COOK) to enough water to make a 1L solution. How many grams of barium hydroxide is needed to shift the pH of this solution to 6? (This question was previously answered. The answer is not 19.4
How many moles of acetic acid will react with 18.25 ml of 0.7500 M NaOH? Calculate...
How many moles of acetic acid will react with 18.25 ml of 0.7500 M NaOH? Calculate the mass (in grams) of acetic acid in 10.00 ml of a solution which contains 0.0083 moles of acetic acid. Assuming that the 10.00 ml sample has an overall mass of 10.00g. Based on the above answer, calculate the percent of this total mass which is due to acetic acid.
1.a)How many milliliters of 0.0998 M NaOH are required to “neutralize” (react completely) with 0.305 g...
1.a)How many milliliters of 0.0998 M NaOH are required to “neutralize” (react completely) with 0.305 g of benzoic acid, C6H5COOH, (Molar mass = 122.12g/mol). b)What is the pH of the resulting solution after the “neutralization” reaction (that is after the NaOH solution has been added to the benzoic acid)? pKa of benzoic acid is 4.20. (You may assume the solid benzoic acid sample was dissolved in 25.0 mL of distilled, deionized water before being reacted with the base to assist...
Sulfurous Acid reacts with sodium hydroxide to produce water and sodium sulfate. 1) write a balanced...
Sulfurous Acid reacts with sodium hydroxide to produce water and sodium sulfate. 1) write a balanced chemical reaction for this system. 2) determine the number of moles of sulfurous acid in 50.00 grams of sulfurous acid. 3) how many moles of sodium sulfate will be produced by the reaction of 50.00 grams of sulfurous acid with sufficient NaOH? 4) how many grams of sodium sulfate will be produced by the reaction of 50.00 grams of sulfurous acid with sufficient NaOH?...
The acid ionization constant Ka of benzoic acid (C6H5COOH; HA) is 6.5 ⨯ 10-5. (1) Calculate...
The acid ionization constant Ka of benzoic acid (C6H5COOH; HA) is 6.5 ⨯ 10-5. (1) Calculate the pH of 2.0L of 0.20 M benzoic acid solution. (2) After adding 8.0 g of NaOH (molar mass: 40 g/mol) to 2.0 L of a 0.20 M benzoic acid solution, Calculate the pH. (3) The solution (2) made above is a buffer solution. 2.0 L of 0.1 M NaOH aqueous solution was added to this solution. After adding more, calculate the pH of...
you select the amino acid Cysteine (pKa=8.2) and dissolve 0.1 moles in 1 liter of water...
you select the amino acid Cysteine (pKa=8.2) and dissolve 0.1 moles in 1 liter of water in order to make a buffer solution. You then adjust the pH to 7.2, but then accidentally add 0.03 moles of HCl to the solution. is the solution still a good buffer? Please help me understand how to use the number of moles added to solve the problem. I can't seem to understand how the amount of moles added relates to the amino acid's...
Titration of acetic acid: How to calculate moles of NaOH added Moles of acetic acid neutralized...
Titration of acetic acid: How to calculate moles of NaOH added Moles of acetic acid neutralized by NaOH Mass of acetic acid Mass % of acetic acid in solution Average mass % of acetic acid
a) A solution was prepared by dissolving 0.02 moles of acetic acid (HOAc; pKa = 4.8)...
a) A solution was prepared by dissolving 0.02 moles of acetic acid (HOAc; pKa = 4.8) in water to give 1 liter of solution. What is the pH? b) To this solution was then added 0.008 moles of concentrated sodium hydroxide (NaOH). What is the new pH? (In this problem, you may ignore changes in volume due to the addition of NaOH). c) An additional 0.012 moles of NaOH is then added. What is the pH?
1) How many moles of acid are there in 17 ml of a 7.1 M HCl...
1) How many moles of acid are there in 17 ml of a 7.1 M HCl solution? 2) 18 ml of a 1.0 M HCl solution was added to a flask and titrated against a solution of 3.8 M NaOH. How many ml of the NaOH solution was required to neutralize the acid? 3) What volume (in liters) of a 2.8 M NaOH solution would neutralize 4.8 moles of H2SO4 (diprotic)? 4) Using the formula M1V1 = M2V2, calculate the...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT