Question

Titration of acetic acid:

How to calculate moles of NaOH added

Moles of acetic acid neutralized by NaOH

Mass of acetic acid

Mass % of acetic acid in solution

Average mass % of acetic acid

Answer 1

in a titration, we need to relate

moles of NAOH to mol of Hacetic acid

so

NaOH + CH3COOH = H2O + NaCH3COO

a)

How to calculate moles of NaOH added

mol of NaOH added cna be obtained via

Volume of NaOH used (from buret readings) and M = molarity of standard

mol of NaOH = Molarity * Volume

b)

Moles of acetic acid neutralized by NaOH

the ratio is 1:1

so moles of NaOH = mol of acetic acid

c)

Mass of acetic acid

by definiton

Mass of acetic acid = mol of acetic acid * Molar Mass of Acetic acid

d)

Mass % of acetic acid in solution

% acetic acid = mass of acetic acid / total solution mass * 100%

e)

Average mass % of acetic acid

% mass of acetic acid --> sum of all sample's mass % / total samples