Question

17. In glycolysis under aerobic conditions in cells, glucose is made into hydrogen gas (sorta) and two pyruvic acid.

                                                      C₆H₁₂O_6(aq) à 2 C₃H₄O_{3 (aq)} + 2 H_{2 (g)}

a. According to this equation, how many moles of pyruvic acid could be made from 360 moles of glucose?

b. According to this equation, how many moles of pyruvic acid could be made from 360 g glucose? (MM_glucose = 180 g/mol)

c. According to this equation, how many grams of pyruvic acid could be made from 36 moles of glucose? (MM_{pyruvic acid} = 88 g/mol)

d. According to this equation, how many grams of pyruvic acid could be made from 36 grams of glucose? (MM_{pyruvic acid} = 88 g/mol)

  

Answer 1

C₆H₁₂O_6(aq) -----> 2 C₃H₄O_{3 (aq)} + 2 H_{2 (g)}

1 equivalent of glucose produces 2 equivalent of pyruvic acid and 2 equivalent of H₂ gas.

A) 360 moles of glucose can produce 360 * 2 => 720 moles of pyruvic acid

B) 360 g of glucose => 360 g/ 180 g/mol => 2 moles of glucose

So 2 moles of glucose can produce 2 * 2 = 4 moles of pyruvic acid.

C) 36 moles of glucose can produce 36 * 2 = 72 moles of pyruvic acid

so 72 moles * 88 g/mol => 6336 g of pyruvic acid.

D) 36 g of glucose = 36 g / 180 g/mol => 0.2 moles

so 0.2 * 2 = 0.4 moles of pyruvic acid could be formed.

0.4 moles * 88 g/mol => 35.2 g of pyruvic acid can be formed.