Determine the total number of valence electrons for the following molecules or ions.
(a) CHCl3
(b) PO43−
(c) Ca(NO3)2
(a) CHCl3 = 1x4+1x1+3x7 = 26 valence electrons
since carbon is 4th group element, H is 1st group element and Cl is 7th group element
(b) PO43− = 1x5+4x6+3 = 32 valence electrons
since P is 5th group element, O is 6th group element and 3 electrons for negative charge
(c) Ca(NO3)2 = 1x2+2x[1x5+3x6] = 48 velence electrons
since Ca is 2nd group element, N is 5th group element, O is 6th group element
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