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What is the pH of a solution made by dissolving 7.91 grams of calcium fluoride in...

What is the pH of a solution made by dissolving 7.91 grams of calcium fluoride in enough water to make 6.0×102 mL of solution? The Ka for HF is 6.8x10–4.
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Answer #1

Ans. #Step 1: [CaF2] = Moles / Vol. in liters = (Mass / MW) / Vol. in liters

                                    = (7.91 g / 78.0748064 g/ mol) / 0.600 L

                                    = 0.169 M

# 1 mol CaF2 consists of 2 mol F-.

So,

            [F-] = 2 x [CaF2] = 2 x 0.169 M = 0.338 M

# Step 2:    

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