Question

**Calculate the amount of H _{2}O required to make
a solution of 4 mM, 158 mM, 0.1 g/L and 5 g/L of aqueous sodium
sulfite solution.** Show complete working out to determine
the amount of H

Answer #1

**a. Concentration = 4mM = 4 ×
10 ^{-3} M**

Moles of Sodium Sulfite / Volume of
H_{2}O = 4 × 10^{-3} M

Therefore, **In 4 milimoles
Sodium Sulfite, 1 L volume of water is
needed.**

**b.**
**Concentration = 158mM = 0.158M**

Moles of Sodium Sulfite / Volume of H_{2}O = 0.158M

Therefore, **In 158 milimoles Sodium Sulfite, 1 L volume
of water is needed.**

**c.** **Concentration = 0.1 g/L**

Therefore, **In 0.1 gram Sodium Sulfite, 1 L volume of
water is needed.**

**d.** **Concentration = 5 g/L**

Therefore, **In 5 gram Sodium Sulfite, 1 L volume of water
is needed.**

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