Question

1) In a bacterial culture, the number of bacteria, f(t), is defined by the equation f(t) = Be0.02t where B is a constant, and t is the time elapsed in minutes the initial number of bacteria is 1000 . Note: initial number of bacteria means the number at the start or t = 0 A. compute for the constant B B. determine the number of bacteria after 50 minutes

2) In a certain bacterial culture the number of bacterial cells was counted to be 200 at the start of incubation. The growth of bacteria follows the exponential growth equation as follows f(t) = Be0.04t ,Where t is the time in minutes and f(t) is the number of cells. A. compute for the constant B B. Find the number of bacteria after 1 hour.

Answer #1

Solve: (5*2=10 marks)
log3x+log3(x+2)=log38
2(-x + 3) = 18(2x+4)
Divide 3x3 + 2x2 – 2 by x –
3
Find the inverse function f-1(x) of the
function y = f(x) =
In a bacterial culture, the number of bacteria, f(t), is
defined by the equation
f(t) = Be0.02t where B is a constant, and t is the time elapsed
in minutes
If the number of bacteria at t= 5sec is 1000. find the number of
bacteria in
30minutes.

A given bacteria culture initially contains 1500 bacteria and
doubles every half hour. The number of bacteria p at a given time t
(in minutes) is given by the formula p(t)=1500e^(kt) for some
constant k. (You will need to find k to answer the following.)
a) Find the size of the bacterial population after 110
minutes.
b) Find the size of the bacterial population after 8 hours.

At time t = 0 a bacterial culture weighs 1 gram. Two
hours later, the culture weighs 4 grams. The maximum weight of the
culture is 20 grams. Find the culture’s weight after 4
hours.
Write the general form of equation for number of bacteria at
time t with constants.
Applying initial condition, what is the value of b.
Applying next condition, what is the value of k?
Find the culture’s weight after 4 hours.

The population of a bacteria in a culture grows at a rate
proportional to the number of bacteria present at time t. After 3
hours it is observed that 400 bacteria are present. After 10 hours
2000 bacteria are present. What was the initial number of
bacteria?

The population of bacteria in a culture grows at a rate
proportional to the number of bacteria present at time t. After 2
hours from the beginning, it is observed that 500 bacteria are
present. After 5 hours (from the beginning), 1500 bacteria are
present. What is the initial number of bacteria P0 ?
Hint: Use P(t) = P0ekt
A - 240 at beggining
B - 198 at beggining
C - 541 at the beggining
D - None of the...

Growth Curves and Logistic Equation
You are working with a culture of Chinese Hamster Ovary Cells
(CHO). Given:
-Specific growth rate=1.2 days^-1
-Initial cell population=10^5 cells
-Maximum population that can be sustained by the
environment=10^8 cells
-There is a lag phase, 0 days<t<1 days, during which no
growth occurs. Exponential growth begins at t=1 day.
Write an equation that describes the number of cells as a
function of time. Plot cell concentration vs time on a semilog
plot. On your...

If the growth rate of bacteria in a culture medium is directly
proportional to the difference between the number of bacteria and a
certain optimal number N¯, derive an expression for the number of
bacteria n as a function of the time t given that the initial
number of bacteria placed in the culture mediam is N0 and that the
constant of proportionality is λ. Sketch, by inspection, the graph
of n = n(t). How long does it take for...

A bacteria culture initially contains 40 cells and grows at a
rate proportional to its size.
After 2 hours the population has increased to 120.
a) Find an expression (in exact simplest form) for the number of
bacteria after t hours.
b) Find the rate of growth at t = 5 hours. Round your final answer
to nearest whole number.

1.
Find the
following for a savings account in which interest is compounded
continuously.
Initial Investment
Annual Rate
Time to Double
Amt. after 10 years
a.
$18,000
5.5
%
_____________
______________
b.
$12,500
_____________
20 years
______________
c.
$500
__________
___
_____________
$1,292.85
2.
The number of bacteria in a culture is increasing according to
the law of exponential
growth. There are 125 bacteria in the culture after 2 hours and
350 bacteria after 4 hours.
a.
Find the initial...

1. Calculate the growth rate and generation time of the
embryoid body that grow from 500 to 100,000,000 over 12 hours in
logarithmic phase.
2. Assume that the generation time of bacteria is 90 minutes
and the number of cells at the start of cultivation is 1000 cells
that start log phase. How many bacteria will exist after 8 hours of
logarithmic growth?
Please write correctly and explain the process in
detail.?

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