A common way to make hydrogen in the labratory is to place a metal such as zinc in hydrochloric acid. The hydrochloric acid reacts with the metal to produce hydrogen gas, which is then collected over water. Suppose a student carries out this reaction and collects a total of 154.4 mL of gas at a pressure of 742 mmHg and a temperature of 25 degrees Celcius. What mass of hydrogen (in mg) does the student collect?
Subtract out the water vapor pressure as you were given the
total pressure of the collected gas including the water
vapor.
V=154.4 mL (= .1544 L)
P(Total)= 742 mmHg (=.9763 atm)
P(H2O) @ 25 C= 23.78 mmHg (=.031289 atm)
T= 25 C (=298K)
P(total)= p(H2O)+p(H2) --> p(H2) +.031289=0.9763
So p(H2) = 0.9763 atm - 0.031289 atm = 0.9450 atm H2
n=(PV)/(RT) --> (0.9450 atm * .1544L)/(.08206 * 298K)=
.00597 mol H2
.00597 mol H2 * 2.016g H2 * 1000mg = 12.029 mg H2
This rounds to 12.0 mg
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