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Methanol vapor can decompose at high temperatures, resulting in the following equilibrium. CH3OH(g) <--> CO(g) +...

Methanol vapor can decompose at high temperatures, resulting in the following equilibrium.

CH3OH(g) <--> CO(g) + 2H2(g)

A 4.72-g sample of liquid CH3OH is added to an evacuated 1.00-L container and heated to 250°C. The methanol vaporizes and then gradually decomposes according to the reaction above. After equilibrium is reached, the mixture of gases is examined and the concentration of H2(g) is found to be 8.25 times the concentration of CH3OH(g). Use this information to find the numerical value of the equilibrium constant.

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