Question

Chris performs an experiment in which he adds 6.52 g KNO3 to 76.55 mL of deionized...

Chris performs an experiment in which he adds 6.52 g KNO3 to 76.55 mL of deionized water in a coffee cup calorimeter. He calculates the enthalpy change of the solution for the process to be +196.12 J. This value can be expressed as the molar enthalpy change of dissolution for KNO3, in kJ/mol. What is Jorge's molar enthalpy change of dissolution (kJ/mol)?

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Answer #1

moles of KNO3 = mass/molarmass = 6.52/101 = 0.064 moles

0.064 moles of KNO3 enthalpy change ------> +196.12 J

1 mole of KNO3 enthalpy change ------> 196.12*1/0.064

                                                             = 3064.4 J

then in KJ/mol is represented as = 3.0644 KJ/mol

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