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12) An organic compound contains C, H, and O. The percentages of H and C are...

12) An organic compound contains C, H, and O. The percentages of H and C are 6.73% H, and 39.99% C by mass. The molar mass is 60.06 u. What is the molecular formula of the compound? A) CH2O B) C3H6O3 C) C2H3O2 D) C2H4O2 E) C4H8O4

1) A 10.0 g sample of bismuth tribromide, BiBr3, contains: A) 5.360 × 1022 total number of ions B) 0.322 mol BiBr3 C) 3.14 × 1022 formula units BiBr3 D) 1.34 × 1022 bromide ions E) 4.020 × 1022 total number of ions

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Answer #1

12) In the organic compound

Percentage of H = 6.37 %; Percentage of C = 39.99 %; Hence percentage of O = 100 - (6.37 + 39.99) = 53.64 %

Element Percentage Atomic mass Relative no of atoms simplest ratio
C 39.99 12 39.99/12 = 3.33 3.33/3.33 = 1
H 6.37 1 6.37/1 = 6.37 6.37 / 3.33 2
O 53.64 16 53.64/16 = 3.35 3.35/3.33 1

Hence, the empirical formula = CH2O

Empirical formula mass = 30 u

n= Molecular mass / Empirical formula mass = 60.06 / 30 2

Hence, molecular formula = (CH2O)2 = C2H4O2 = CH3COOH

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