Combustion of 1.000g of an organic compound that contains C, H and O produces 2.360g CO2 and 0.640g H2O. What is the empirical formula of the compound? Please show work
Solution:
1) mass of each element:
carbon ⇒ 2.360 g x (12.011 / 44.0098) = 0.644 g
hydrogen ⇒ 0.640 g x (2.016 / 18.015) = 0.071 g
oxygen ⇒ 1.000 minus (0.644+0.0711) = 0.285 g
Notice that there was oxygen in the compound and that the problem did not tell you that.
2) moles of each element:
carbon ⇒ 0.644 g / 12.011 g/mol = 0.054 mol
hydrogen ⇒ 0.0711 g / 1.0 g/mol = 0.071mol
oxygen ⇒ 0.285 g / 16.00 g/mol = 0.0178 mol
3) Look for smallest whole-number ratio:
carbon ⇒ 0.054 / 0.0178 = 3
hydrogen ⇒ 0.0711 / 0.0178 = 4
oxygen ⇒ 0.0178 / 0.0178 = 1
empirical fromula
= c3 h4 O
please do tell me if its wrong. il recheck into it and tell the correct answer.
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