In the complex Ni(Br)(NO)(PPh3)2 formation reaction, the stoichiometric ratios are 1:1:
So, If we calculate the number of moles of each of the reagents, the smallest of them corresponds to the limiting reagent:
For Ni(Br)2(PPh3)2 (MW=743.07g/mol)
For NaNO2 (MW=69g/mol)
For PPh3 (MW=262.69g/mol)
The reagent Ni(Br)2(PPh3)2 is the limiting reagent, so the the theoretical grams of the complex Ni(Br)(NO)(PPh3)2 (MW=693.18g/mol) are:
Thus the percentage of yield is:
Get Answers For Free
Most questions answered within 1 hours.